5(c-6)=(c+11)+24

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Solution for 5(c-6)=(c+11)+24 equation: 



5(c-6)=(c+11)+24

We move all terms to the left:

5(c-6)-((c+11)+24)=0

We multiply parentheses

5c-((c+11)+24)-30=0



We calculate terms in parentheses: -((c+11)+24), so:

(c+11)+24

We get rid of parentheses

c+11+24

We add all the numbers together, and all the variables

c+35

Back to the equation:

-(c+35)



We get rid of parentheses

5c-c-35-30=0

We add all the numbers together, and all the variables

4c-65=0

We move all terms containing c to the left, all other terms to the right

4c=65

c=65/4

c=16+1/4

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