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12-5x=6x^2
We move all terms to the left:
12-5x-(6x^2)=0
determiningTheFunctionDomain -6x^2-5x+12=0
a = -6; b = -5; c = +12;
Δ = b2-4ac
Δ = -52-4·(-6)·12
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{313}}{2*-6}=\frac{5-\sqrt{313}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{313}}{2*-6}=\frac{5+\sqrt{313}}{-12} $
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