5(c-5)+3=2+c-24

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Solution for 5(c-5)+3=2+c-24 equation: 



5(c-5)+3=2+c-24

We move all terms to the left:

5(c-5)+3-(2+c-24)=0

We add all the numbers together, and all the variables

5(c-5)-(c-22)+3=0

We multiply parentheses

5c-(c-22)-25+3=0

We get rid of parentheses

5c-c+22-25+3=0

We add all the numbers together, and all the variables

4c=0

c=0/4

c=0

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