2(2t+4)=(3+4)+(24-8t)

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Solution for 2(2t+4)=(3+4)+(24-8t) equation: 



2(2t+4)=(3+4)+(24-8t)

We move all terms to the left:

2(2t+4)-((3+4)+(24-8t))=0

We add all the numbers together, and all the variables

2(2t+4)-(7+(-8t+24))=0

We multiply parentheses

4t-(7+(-8t+24))+8=0



We calculate terms in parentheses: -(7+(-8t+24)), so:

7+(-8t+24)

determiningTheFunctionDomain
(-8t+24)+7

We get rid of parentheses

-8t+24+7

We add all the numbers together, and all the variables

-8t+31

Back to the equation:

-(-8t+31)



We get rid of parentheses

4t+8t-31+8=0

We add all the numbers together, and all the variables

12t-23=0

We move all terms containing t to the left, all other terms to the right

12t=23

t=23/12

t=1+11/12

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