5(c-4)+2=27

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Solution for 5(c-4)+2=27 equation: 



5(c-4)+2=27

We move all terms to the left:

5(c-4)+2-(27)=0

We add all the numbers together, and all the variables

5(c-4)-25=0

We multiply parentheses

5c-20-25=0

We add all the numbers together, and all the variables

5c-45=0

We move all terms containing c to the left, all other terms to the right

5c=45

c=45/5

c=9

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