7x+1=7(3x-2)

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Solution for 7x+1=7(3x-2) equation: 



7x+1=7(3x-2)

We move all terms to the left:

7x+1-(7(3x-2))=0



We calculate terms in parentheses: -(7(3x-2)), so:

7(3x-2)

We multiply parentheses

21x-14

Back to the equation:

-(21x-14)



We get rid of parentheses

7x-21x+14+1=0

We add all the numbers together, and all the variables

-14x+15=0

We move all terms containing x to the left, all other terms to the right

-14x=-15

x=-15/-14

x=1+1/14

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