5(c-3)=2(c+3)+3c

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Solution for 5(c-3)=2(c+3)+3c equation: 



5(c-3)=2(c+3)+3c

We move all terms to the left:

5(c-3)-(2(c+3)+3c)=0

We multiply parentheses

5c-(2(c+3)+3c)-15=0



We calculate terms in parentheses: -(2(c+3)+3c), so:

2(c+3)+3c

We add all the numbers together, and all the variables

3c+2(c+3)

We multiply parentheses

3c+2c+6

We add all the numbers together, and all the variables

5c+6

Back to the equation:

-(5c+6)



We get rid of parentheses

5c-5c-6-15=0

We add all the numbers together, and all the variables

-21!=0

There is no solution for this equation

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