5(c+3)=152(2c-1)

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Solution for 5(c+3)=152(2c-1) equation: 



5(c+3)=152(2c-1)

We move all terms to the left:

5(c+3)-(152(2c-1))=0

We multiply parentheses

5c-(152(2c-1))+15=0



We calculate terms in parentheses: -(152(2c-1)), so:

152(2c-1)

We multiply parentheses

304c-152

Back to the equation:

-(304c-152)



We get rid of parentheses

5c-304c+152+15=0

We add all the numbers together, and all the variables

-299c+167=0

We move all terms containing c to the left, all other terms to the right

-299c=-167

c=-167/-299

c=167/299

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