(X+1)/8=2-(x+2)/3

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Solution for (X+1)/8=2-(x+2)/3 equation: 



(X+1)/8=2-(X+2)/3

We move all terms to the left:

(X+1)/8-(2-(X+2)/3)=0

We calculate fractions


X/()+(-(2-(X+2)*8)/()=0



We calculate terms in parentheses: +(-(2-(X+2)*8)/(), so:

-(2-(X+2)*8)/(

We multiply all the terms by the denominator


-(2-(X+2)*8)



We calculate terms in parentheses: -(2-(X+2)*8), so:

2-(X+2)*8

determiningTheFunctionDomain
-(X+2)*8+2

We multiply parentheses

-8X-16+2

We add all the numbers together, and all the variables

-8X-14

Back to the equation:

-(-8X-14)



We get rid of parentheses

8X+14

Back to the equation:

+(8X+14)



We get rid of parentheses

X/()+8X+14=0

We multiply all the terms by the denominator


X+8X*()+14*()=0

We add all the numbers together, and all the variables

X+8X*()=0

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