5(c+12)=4(3c+10)

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Solution for 5(c+12)=4(3c+10) equation: 



5(c+12)=4(3c+10)

We move all terms to the left:

5(c+12)-(4(3c+10))=0

We multiply parentheses

5c-(4(3c+10))+60=0



We calculate terms in parentheses: -(4(3c+10)), so:

4(3c+10)

We multiply parentheses

12c+40

Back to the equation:

-(12c+40)



We get rid of parentheses

5c-12c-40+60=0

We add all the numbers together, and all the variables

-7c+20=0

We move all terms containing c to the left, all other terms to the right

-7c=-20

c=-20/-7

c=2+6/7

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