36-10x2/5=11

Solution for 36-10x2/5=11 equation:

36-10x^2/5=11

We move all terms to the left:

36-10x^2/5-(11)=0

We add all the numbers together, and all the variables

-10x^2/5+25=0

We multiply all the terms by the denominator


-10x^2+25*5=0

We add all the numbers together, and all the variables

-10x^2+125=0

a = -10; b = 0; c = +125;
Δ = b2-4ac
Δ = 02-4·(-10)·125
Δ = 5000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5000}=\sqrt{2500*2}=\sqrt{2500}*\sqrt{2}=50\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50\sqrt{2}}{2*-10}=\frac{0-50\sqrt{2}}{-20}
=-\frac{50\sqrt{2}}{-20}
=-\frac{5\sqrt{2}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50\sqrt{2}}{2*-10}=\frac{0+50\sqrt{2}}{-20}
=\frac{50\sqrt{2}}{-20}
=\frac{5\sqrt{2}}{-2}
$