5(b-4)-3(b+4)=6

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Solution for 5(b-4)-3(b+4)=6 equation:


Simplifying
5(b + -4) + -3(b + 4) = 6

Reorder the terms:
5(-4 + b) + -3(b + 4) = 6
(-4 * 5 + b * 5) + -3(b + 4) = 6
(-20 + 5b) + -3(b + 4) = 6

Reorder the terms:
-20 + 5b + -3(4 + b) = 6
-20 + 5b + (4 * -3 + b * -3) = 6
-20 + 5b + (-12 + -3b) = 6

Reorder the terms:
-20 + -12 + 5b + -3b = 6

Combine like terms: -20 + -12 = -32
-32 + 5b + -3b = 6

Combine like terms: 5b + -3b = 2b
-32 + 2b = 6

Solving
-32 + 2b = 6

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '32' to each side of the equation.
-32 + 32 + 2b = 6 + 32

Combine like terms: -32 + 32 = 0
0 + 2b = 6 + 32
2b = 6 + 32

Combine like terms: 6 + 32 = 38
2b = 38

Divide each side by '2'.
b = 19

Simplifying
b = 19

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