7y+3=3(1+2y)+y

Solution for 7y+3=3(1+2y)+y equation:

Simplifying
7y + 3 = 3(1 + 2y) + y

Reorder the terms:
3 + 7y = 3(1 + 2y) + y
3 + 7y = (1 * 3 + 2y * 3) + y
3 + 7y = (3 + 6y) + y

Combine like terms: 6y + y = 7y
3 + 7y = 3 + 7y

Add '-3' to each side of the equation.
3 + -3 + 7y = 3 + -3 + 7y

Combine like terms: 3 + -3 = 0
0 + 7y = 3 + -3 + 7y
7y = 3 + -3 + 7y

Combine like terms: 3 + -3 = 0
7y = 0 + 7y
7y = 7y

Add '-7y' to each side of the equation.
7y + -7y = 7y + -7y

Combine like terms: 7y + -7y = 0
0 = 7y + -7y

Combine like terms: 7y + -7y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.