5(b+7)=4(b-3)

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Solution for 5(b+7)=4(b-3) equation: 



5(b+7)=4(b-3)

We move all terms to the left:

5(b+7)-(4(b-3))=0

We multiply parentheses

5b-(4(b-3))+35=0



We calculate terms in parentheses: -(4(b-3)), so:

4(b-3)

We multiply parentheses

4b-12

Back to the equation:

-(4b-12)



We get rid of parentheses

5b-4b+12+35=0

We add all the numbers together, and all the variables

b+47=0

We move all terms containing b to the left, all other terms to the right

b=-47

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