4y+5-3(-6y-1)=4(y-2)

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Solution for 4y+5-3(-6y-1)=4(y-2) equation: 



4y+5-3(-6y-1)=4(y-2)

We move all terms to the left:

4y+5-3(-6y-1)-(4(y-2))=0

We multiply parentheses

4y+18y-(4(y-2))+3+5=0



We calculate terms in parentheses: -(4(y-2)), so:

4(y-2)

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)



We add all the numbers together, and all the variables

22y-(4y-8)+8=0

We get rid of parentheses

22y-4y+8+8=0

We add all the numbers together, and all the variables

18y+16=0

We move all terms containing y to the left, all other terms to the right

18y=-16

y=-16/18

y=-8/9

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