3/10(-20x-30)=42

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Solution for 3/10(-20x-30)=42 equation: 



3/10(-20x-30)=42

We move all terms to the left:

3/10(-20x-30)-(42)=0



Domain of the equation: 10(-20x-30)!=0

x∈R



We multiply all the terms by the denominator


-42*10(-20x-30)+3=0

Wy multiply elements

-420x(-+3=0

We use the square of the difference formula

-420x(-3=0

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