5(b+3)=4(b+4)

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Solution for 5(b+3)=4(b+4) equation: 



5(b+3)=4(b+4)

We move all terms to the left:

5(b+3)-(4(b+4))=0

We multiply parentheses

5b-(4(b+4))+15=0



We calculate terms in parentheses: -(4(b+4)), so:

4(b+4)

We multiply parentheses

4b+16

Back to the equation:

-(4b+16)



We get rid of parentheses

5b-4b-16+15=0

We add all the numbers together, and all the variables

b-1=0

We move all terms containing b to the left, all other terms to the right

b=1

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