4(3-x)+1=2x+2-5(1-4x)

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Solution for 4(3-x)+1=2x+2-5(1-4x) equation: 



4(3-x)+1=2x+2-5(1-4x)

We move all terms to the left:

4(3-x)+1-(2x+2-5(1-4x))=0

We add all the numbers together, and all the variables

4(-1x+3)-(2x+2-5(-4x+1))+1=0

We multiply parentheses

-4x-(2x+2-5(-4x+1))+12+1=0



We calculate terms in parentheses: -(2x+2-5(-4x+1)), so:

2x+2-5(-4x+1)

determiningTheFunctionDomain
2x-5(-4x+1)+2

We multiply parentheses

2x+20x-5+2

We add all the numbers together, and all the variables

22x-3

Back to the equation:

-(22x-3)



We add all the numbers together, and all the variables

-4x-(22x-3)+13=0

We get rid of parentheses

-4x-22x+3+13=0

We add all the numbers together, and all the variables

-26x+16=0

We move all terms containing x to the left, all other terms to the right

-26x=-16

x=-16/-26

x=8/13

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