3(m-2)+4m=15

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Solution for 3(m-2)+4m=15 equation: 



3(m-2)+4m=15

We move all terms to the left:

3(m-2)+4m-(15)=0

We add all the numbers together, and all the variables

4m+3(m-2)-15=0

We multiply parentheses

4m+3m-6-15=0

We add all the numbers together, and all the variables

7m-21=0

We move all terms containing m to the left, all other terms to the right

7m=21

m=21/7

m=3

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