x+20=3(x-2)

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Solution for x+20=3(x-2) equation: 



x+20=3(x-2)

We move all terms to the left:

x+20-(3(x-2))=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

x-3x+6+20=0

We add all the numbers together, and all the variables

-2x+26=0

We move all terms containing x to the left, all other terms to the right

-2x=-26

x=-26/-2

x=+13

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