5(b+2)+b+2=20

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Solution for 5(b+2)+b+2=20 equation: 



5(b+2)+b+2=20

We move all terms to the left:

5(b+2)+b+2-(20)=0

We add all the numbers together, and all the variables

b+5(b+2)-18=0

We multiply parentheses

b+5b+10-18=0

We add all the numbers together, and all the variables

6b-8=0

We move all terms containing b to the left, all other terms to the right

6b=8

b=8/6

b=1+1/3

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