-7(8b+2)=40-2b

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Solution for -7(8b+2)=40-2b equation:



-7(8b+2)=40-2b
We move all terms to the left:
-7(8b+2)-(40-2b)=0
We add all the numbers together, and all the variables
-7(8b+2)-(-2b+40)=0
We multiply parentheses
-56b-(-2b+40)-14=0
We get rid of parentheses
-56b+2b-40-14=0
We add all the numbers together, and all the variables
-54b-54=0
We move all terms containing b to the left, all other terms to the right
-54b=54
b=54/-54
b=-1

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