5(a-4)=2(6+a)

Solution for 5(a-4)=2(6+a) equation:

5(a-4)=2(6+a)

We move all terms to the left:

5(a-4)-(2(6+a))=0

We add all the numbers together, and all the variables

5(a-4)-(2(a+6))=0

We multiply parentheses

5a-(2(a+6))-20=0


We calculate terms in parentheses: -(2(a+6)), so:

2(a+6)

We multiply parentheses

2a+12

Back to the equation:

-(2a+12)


We get rid of parentheses

5a-2a-12-20=0

We add all the numbers together, and all the variables

3a-32=0

We move all terms containing a to the left, all other terms to the right

3a=32

a=32/3

a=10+2/3