4(20+5+20)=3(2x+12)

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Solution for 4(20+5+20)=3(2x+12) equation: 



4(20+5+20)=3(2x+12)

We move all terms to the left:

4(20+5+20)-(3(2x+12))=0

We add all the numbers together, and all the variables

-(3(2x+12))+445=0



We calculate terms in parentheses: -(3(2x+12)), so:

3(2x+12)

We multiply parentheses

6x+36

Back to the equation:

-(6x+36)



We get rid of parentheses

-6x-36+445=0

We add all the numbers together, and all the variables

-6x+409=0

We move all terms containing x to the left, all other terms to the right

-6x=-409

x=-409/-6

x=68+1/6

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