11(2x+5)-20=4(3x+6)+21

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Solution for 11(2x+5)-20=4(3x+6)+21 equation: 



11(2x+5)-20=4(3x+6)+21

We move all terms to the left:

11(2x+5)-20-(4(3x+6)+21)=0

We multiply parentheses

22x-(4(3x+6)+21)+55-20=0



We calculate terms in parentheses: -(4(3x+6)+21), so:

4(3x+6)+21

We multiply parentheses

12x+24+21

We add all the numbers together, and all the variables

12x+45

Back to the equation:

-(12x+45)



We add all the numbers together, and all the variables

22x-(12x+45)+35=0

We get rid of parentheses

22x-12x-45+35=0

We add all the numbers together, and all the variables

10x-10=0

We move all terms containing x to the left, all other terms to the right

10x=10

x=10/10

x=1

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