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5(a+2)=2(3a+5)
We move all terms to the left:
5(a+2)-(2(3a+5))=0
We multiply parentheses
5a-(2(3a+5))+10=0
We calculate terms in parentheses: -(2(3a+5)), so:We get rid of parentheses
2(3a+5)
We multiply parentheses
6a+10
Back to the equation:
-(6a+10)
5a-6a-10+10=0
We add all the numbers together, and all the variables
-a=0
a=0/-1
a=0
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