5(K+2)-4=7k-2(2k+1)

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Solution for 5(K+2)-4=7k-2(2k+1) equation: 



5(+2)-4=7K-2(2K+1)

We move all terms to the left:

5(+2)-4-(7K-2(2K+1))=0

We add all the numbers together, and all the variables

-(7K-2(2K+1))-4+52=0

We add all the numbers together, and all the variables

-(7K-2(2K+1))+48=0



We calculate terms in parentheses: -(7K-2(2K+1)), so:

7K-2(2K+1)

We multiply parentheses

7K-4K-2

We add all the numbers together, and all the variables

3K-2

Back to the equation:

-(3K-2)



We get rid of parentheses

-3K+2+48=0

We add all the numbers together, and all the variables

-3K+50=0

We move all terms containing K to the left, all other terms to the right

-3K=-50

K=-50/-3

K=16+2/3

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