(5/6)x+(4/3)=(2/3)x

Solution for (5/6)x+(4/3)=(2/3)x equation:

(5/6)x+(4/3)=(2/3)x

We move all terms to the left:

(5/6)x+(4/3)-((2/3)x)=0


Domain of the equation: 6)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 3)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+5/6)x-((+2/3)x)+(+4/3)=0

We multiply parentheses

5x^2-((+2/3)x)+(+4/3)=0

We get rid of parentheses

5x^2-((+2/3)x)+4/3=0

We calculate fractions


5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$