5(I+2)=8(i+-1)

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Solution for 5(I+2)=8(i+-1) equation: 



5(+2)=8(I+-1)

We move all terms to the left:

5(+2)-(8(I+-1))=0

We add all the numbers together, and all the variables

-(8(I-1))+52=0



We calculate terms in parentheses: -(8(I-1)), so:

8(I-1)

We multiply parentheses

8I-8

Back to the equation:

-(8I-8)



We get rid of parentheses

-8I+8+52=0

We add all the numbers together, and all the variables

-8I+60=0

We move all terms containing I to the left, all other terms to the right

-8I=-60

I=-60/-8

I=7+1/2

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