5(9-b)-57=25b-6(2+5b)

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Solution for 5(9-b)-57=25b-6(2+5b) equation: 



5(9-b)-57=25b-6(2+5b)

We move all terms to the left:

5(9-b)-57-(25b-6(2+5b))=0

We add all the numbers together, and all the variables

5(-1b+9)-(25b-6(5b+2))-57=0

We multiply parentheses

-5b-(25b-6(5b+2))+45-57=0



We calculate terms in parentheses: -(25b-6(5b+2)), so:

25b-6(5b+2)

We multiply parentheses

25b-30b-12

We add all the numbers together, and all the variables

-5b-12

Back to the equation:

-(-5b-12)



We add all the numbers together, and all the variables

-5b-(-5b-12)-12=0

We get rid of parentheses

-5b+5b+12-12=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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