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4(x+1)+5x=3(x+1)-2
We move all terms to the left:
4(x+1)+5x-(3(x+1)-2)=0
We add all the numbers together, and all the variables
5x+4(x+1)-(3(x+1)-2)=0
We multiply parentheses
5x+4x-(3(x+1)-2)+4=0
We calculate terms in parentheses: -(3(x+1)-2), so:We add all the numbers together, and all the variables
3(x+1)-2
We multiply parentheses
3x+3-2
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
9x-(3x+1)+4=0
We get rid of parentheses
9x-3x-1+4=0
We add all the numbers together, and all the variables
6x+3=0
We move all terms containing x to the left, all other terms to the right
6x=-3
x=-3/6
x=-1/2
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