5(7x+1)+6=x(3-x)+2-x(7-x)

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Solution for 5(7x+1)+6=x(3-x)+2-x(7-x) equation: 



5(7x+1)+6=x(3-x)+2-x(7-x)

We move all terms to the left:

5(7x+1)+6-(x(3-x)+2-x(7-x))=0

We add all the numbers together, and all the variables

5(7x+1)-(x(-1x+3)+2-x(-1x+7))+6=0

We multiply parentheses

35x-(x(-1x+3)+2-x(-1x+7))+5+6=0



We calculate terms in parentheses: -(x(-1x+3)+2-x(-1x+7)), so:

x(-1x+3)+2-x(-1x+7)

determiningTheFunctionDomain
x(-1x+3)-x(-1x+7)+2

We multiply parentheses

-1x^2+1x^2+3x-7x+2

We add all the numbers together, and all the variables

-4x+2

Back to the equation:

-(-4x+2)



We add all the numbers together, and all the variables

35x-(-4x+2)+11=0

We get rid of parentheses

35x+4x-2+11=0

We add all the numbers together, and all the variables

39x+9=0

We move all terms containing x to the left, all other terms to the right

39x=-9

x=-9/39

x=-3/13

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