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5x^2-3=-4-5(x-x2)
We move all terms to the left:
5x^2-3-(-4-5(x-x2))=0
We add all the numbers together, and all the variables
5x^2-(-4-5(+x-1x^2))-3=0
We calculate terms in parentheses: -(-4-5(+x-1x^2)), so:We get rid of parentheses
-4-5(+x-1x^2)
determiningTheFunctionDomain -5(+x-1x^2)-4
We multiply parentheses
5x^2-5x-4
Back to the equation:
-(5x^2-5x-4)
5x^2-5x^2+5x+4-3=0
We add all the numbers together, and all the variables
5x+1=0
We move all terms containing x to the left, all other terms to the right
5x=-1
x=-1/5
x=-1/5
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