5(6z-1)-2(z+1)=24(z+1)

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Solution for 5(6z-1)-2(z+1)=24(z+1) equation: 



5(6z-1)-2(z+1)=24(z+1)

We move all terms to the left:

5(6z-1)-2(z+1)-(24(z+1))=0

We multiply parentheses

30z-2z-(24(z+1))-5-2=0



We calculate terms in parentheses: -(24(z+1)), so:

24(z+1)

We multiply parentheses

24z+24

Back to the equation:

-(24z+24)



We add all the numbers together, and all the variables

28z-(24z+24)-7=0

We get rid of parentheses

28z-24z-24-7=0

We add all the numbers together, and all the variables

4z-31=0

We move all terms containing z to the left, all other terms to the right

4z=31

z=31/4

z=7+3/4

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