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3x^2+15x+11=0
a = 3; b = 15; c = +11;
Δ = b2-4ac
Δ = 152-4·3·11
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{93}}{2*3}=\frac{-15-\sqrt{93}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{93}}{2*3}=\frac{-15+\sqrt{93}}{6} $
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