5(6y-5)+24=4(5y+2)+19

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Solution for 5(6y-5)+24=4(5y+2)+19 equation: 



5(6y-5)+24=4(5y+2)+19

We move all terms to the left:

5(6y-5)+24-(4(5y+2)+19)=0

We multiply parentheses

30y-(4(5y+2)+19)-25+24=0



We calculate terms in parentheses: -(4(5y+2)+19), so:

4(5y+2)+19

We multiply parentheses

20y+8+19

We add all the numbers together, and all the variables

20y+27

Back to the equation:

-(20y+27)



We add all the numbers together, and all the variables

30y-(20y+27)-1=0

We get rid of parentheses

30y-20y-27-1=0

We add all the numbers together, and all the variables

10y-28=0

We move all terms containing y to the left, all other terms to the right

10y=28

y=28/10

y=2+4/5

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