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1/3X-2X=5
We move all terms to the left:
1/3X-2X-(5)=0
Domain of the equation: 3X!=0We add all the numbers together, and all the variables
X!=0/3
X!=0
X∈R
-2X+1/3X-5=0
We multiply all the terms by the denominator
-2X*3X-5*3X+1=0
Wy multiply elements
-6X^2-15X+1=0
a = -6; b = -15; c = +1;
Δ = b2-4ac
Δ = -152-4·(-6)·1
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{249}}{2*-6}=\frac{15-\sqrt{249}}{-12} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{249}}{2*-6}=\frac{15+\sqrt{249}}{-12} $
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