5(6y+1)-3=4(5y-1)+20

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Solution for 5(6y+1)-3=4(5y-1)+20 equation: 



5(6y+1)-3=4(5y-1)+20

We move all terms to the left:

5(6y+1)-3-(4(5y-1)+20)=0

We multiply parentheses

30y-(4(5y-1)+20)+5-3=0



We calculate terms in parentheses: -(4(5y-1)+20), so:

4(5y-1)+20

We multiply parentheses

20y-4+20

We add all the numbers together, and all the variables

20y+16

Back to the equation:

-(20y+16)



We add all the numbers together, and all the variables

30y-(20y+16)+2=0

We get rid of parentheses

30y-20y-16+2=0

We add all the numbers together, and all the variables

10y-14=0

We move all terms containing y to the left, all other terms to the right

10y=14

y=14/10

y=1+2/5

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