5(6x-2)=3(-8+x)+2

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Solution for 5(6x-2)=3(-8+x)+2 equation: 



5(6x-2)=3(-8+x)+2

We move all terms to the left:

5(6x-2)-(3(-8+x)+2)=0

We add all the numbers together, and all the variables

5(6x-2)-(3(x-8)+2)=0

We multiply parentheses

30x-(3(x-8)+2)-10=0



We calculate terms in parentheses: -(3(x-8)+2), so:

3(x-8)+2

We multiply parentheses

3x-24+2

We add all the numbers together, and all the variables

3x-22

Back to the equation:

-(3x-22)



We get rid of parentheses

30x-3x+22-10=0

We add all the numbers together, and all the variables

27x+12=0

We move all terms containing x to the left, all other terms to the right

27x=-12

x=-12/27

x=-4/9

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