5(6x+2)+2(7-x)+1=3(2x-5)

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Solution for 5(6x+2)+2(7-x)+1=3(2x-5) equation: 



5(6x+2)+2(7-x)+1=3(2x-5)

We move all terms to the left:

5(6x+2)+2(7-x)+1-(3(2x-5))=0

We add all the numbers together, and all the variables

5(6x+2)+2(-1x+7)-(3(2x-5))+1=0

We multiply parentheses

30x-2x-(3(2x-5))+10+14+1=0



We calculate terms in parentheses: -(3(2x-5)), so:

3(2x-5)

We multiply parentheses

6x-15

Back to the equation:

-(6x-15)



We add all the numbers together, and all the variables

28x-(6x-15)+25=0

We get rid of parentheses

28x-6x+15+25=0

We add all the numbers together, and all the variables

22x+40=0

We move all terms containing x to the left, all other terms to the right

22x=-40

x=-40/22

x=-1+9/11

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