5(6+y)-10=9-(2y+3)

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Solution for 5(6+y)-10=9-(2y+3) equation: 



5(6+y)-10=9-(2y+3)

We move all terms to the left:

5(6+y)-10-(9-(2y+3))=0

We add all the numbers together, and all the variables

5(y+6)-(9-(2y+3))-10=0

We multiply parentheses

5y-(9-(2y+3))+30-10=0



We calculate terms in parentheses: -(9-(2y+3)), so:

9-(2y+3)

determiningTheFunctionDomain
-(2y+3)+9

We get rid of parentheses

-2y-3+9

We add all the numbers together, and all the variables

-2y+6

Back to the equation:

-(-2y+6)



We add all the numbers together, and all the variables

5y-(-2y+6)+20=0

We get rid of parentheses

5y+2y-6+20=0

We add all the numbers together, and all the variables

7y+14=0

We move all terms containing y to the left, all other terms to the right

7y=-14

y=-14/7

y=-2

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