-2(1-3x)=22-3(x+6)

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Solution for -2(1-3x)=22-3(x+6) equation: 



-2(1-3x)=22-3(x+6)

We move all terms to the left:

-2(1-3x)-(22-3(x+6))=0

We add all the numbers together, and all the variables

-2(-3x+1)-(22-3(x+6))=0

We multiply parentheses

6x-(22-3(x+6))-2=0



We calculate terms in parentheses: -(22-3(x+6)), so:

22-3(x+6)

determiningTheFunctionDomain
-3(x+6)+22

We multiply parentheses

-3x-18+22

We add all the numbers together, and all the variables

-3x+4

Back to the equation:

-(-3x+4)



We get rid of parentheses

6x+3x-4-2=0

We add all the numbers together, and all the variables

9x-6=0

We move all terms containing x to the left, all other terms to the right

9x=6

x=6/9

x=2/3

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