5(5z-6)=4(z-7)

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Solution for 5(5z-6)=4(z-7) equation: 



5(5z-6)=4(z-7)

We move all terms to the left:

5(5z-6)-(4(z-7))=0

We multiply parentheses

25z-(4(z-7))-30=0



We calculate terms in parentheses: -(4(z-7)), so:

4(z-7)

We multiply parentheses

4z-28

Back to the equation:

-(4z-28)



We get rid of parentheses

25z-4z+28-30=0

We add all the numbers together, and all the variables

21z-2=0

We move all terms containing z to the left, all other terms to the right

21z=2

z=2/21

z=2/21

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