131=3(2+6x)+7x

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Solution for 131=3(2+6x)+7x equation: 



131=3(2+6x)+7x

We move all terms to the left:

131-(3(2+6x)+7x)=0

We add all the numbers together, and all the variables

-(3(6x+2)+7x)+131=0



We calculate terms in parentheses: -(3(6x+2)+7x), so:

3(6x+2)+7x

We add all the numbers together, and all the variables

7x+3(6x+2)

We multiply parentheses

7x+18x+6

We add all the numbers together, and all the variables

25x+6

Back to the equation:

-(25x+6)



We get rid of parentheses

-25x-6+131=0

We add all the numbers together, and all the variables

-25x+125=0

We move all terms containing x to the left, all other terms to the right

-25x=-125

x=-125/-25

x=+5

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