5(5y-2)+4(2y+6)=25(3y+2)-12y

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Solution for 5(5y-2)+4(2y+6)=25(3y+2)-12y equation: 



5(5y-2)+4(2y+6)=25(3y+2)-12y

We move all terms to the left:

5(5y-2)+4(2y+6)-(25(3y+2)-12y)=0

We multiply parentheses

25y+8y-(25(3y+2)-12y)-10+24=0



We calculate terms in parentheses: -(25(3y+2)-12y), so:

25(3y+2)-12y

We add all the numbers together, and all the variables

-12y+25(3y+2)

We multiply parentheses

-12y+75y+50

We add all the numbers together, and all the variables

63y+50

Back to the equation:

-(63y+50)



We add all the numbers together, and all the variables

33y-(63y+50)+14=0

We get rid of parentheses

33y-63y-50+14=0

We add all the numbers together, and all the variables

-30y-36=0

We move all terms containing y to the left, all other terms to the right

-30y=36

y=36/-30

y=-1+1/5

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