16=1/2*4(3+b)

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Solution for 16=1/2*4(3+b) equation: 



16=1/2*4(3+b)

We move all terms to the left:

16-(1/2*4(3+b))=0



Domain of the equation: 2*4(3+b))!=0

b∈R



We add all the numbers together, and all the variables

-(1/2*4(b+3))+16=0

We multiply all the terms by the denominator


-(1+16*2*4(b+3))=0



We calculate terms in parentheses: -(1+16*2*4(b+3)), so:

1+16*2*4(b+3)

determiningTheFunctionDomain
16*2*4(b+3)+1

Wy multiply elements

128b*4+1

Wy multiply elements

512b+1

Back to the equation:

-(512b+1)



We get rid of parentheses

-512b-1=0

We move all terms containing b to the left, all other terms to the right

-512b=1

b=1/-512

b=-1/512

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