5(5y-2)+2(2y+6)=25(3y+2)-14y

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Solution for 5(5y-2)+2(2y+6)=25(3y+2)-14y equation: 



5(5y-2)+2(2y+6)=25(3y+2)-14y

We move all terms to the left:

5(5y-2)+2(2y+6)-(25(3y+2)-14y)=0

We multiply parentheses

25y+4y-(25(3y+2)-14y)-10+12=0



We calculate terms in parentheses: -(25(3y+2)-14y), so:

25(3y+2)-14y

We add all the numbers together, and all the variables

-14y+25(3y+2)

We multiply parentheses

-14y+75y+50

We add all the numbers together, and all the variables

61y+50

Back to the equation:

-(61y+50)



We add all the numbers together, and all the variables

29y-(61y+50)+2=0

We get rid of parentheses

29y-61y-50+2=0

We add all the numbers together, and all the variables

-32y-48=0

We move all terms containing y to the left, all other terms to the right

-32y=48

y=48/-32

y=-1+1/2

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