5(5y-2)+2(2y+6)=25(3y+2)-14

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Solution for 5(5y-2)+2(2y+6)=25(3y+2)-14 equation: 



5(5y-2)+2(2y+6)=25(3y+2)-14

We move all terms to the left:

5(5y-2)+2(2y+6)-(25(3y+2)-14)=0

We multiply parentheses

25y+4y-(25(3y+2)-14)-10+12=0



We calculate terms in parentheses: -(25(3y+2)-14), so:

25(3y+2)-14

We multiply parentheses

75y+50-14

We add all the numbers together, and all the variables

75y+36

Back to the equation:

-(75y+36)



We add all the numbers together, and all the variables

29y-(75y+36)+2=0

We get rid of parentheses

29y-75y-36+2=0

We add all the numbers together, and all the variables

-46y-34=0

We move all terms containing y to the left, all other terms to the right

-46y=34

y=34/-46

y=-17/23

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