5(5x-4)-8(x-3)=x+6/4

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Solution for 5(5x-4)-8(x-3)=x+6/4 equation:



5(5x-4)-8(x-3)=x+6/4
We move all terms to the left:
5(5x-4)-8(x-3)-(x+6/4)=0
We add all the numbers together, and all the variables
5(5x-4)-8(x-3)-(+x+6/4)=0
We multiply parentheses
25x-8x-(+x+6/4)-20+24=0
We get rid of parentheses
25x-8x-x-20+24-6/4=0
We multiply all the terms by the denominator
25x*4-8x*4-x*4-6-20*4+24*4=0
We add all the numbers together, and all the variables
25x*4-8x*4-x*4+10=0
Wy multiply elements
100x-32x-4x+10=0
We add all the numbers together, and all the variables
64x+10=0
We move all terms containing x to the left, all other terms to the right
64x=-10
x=-10/64
x=-5/32

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