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5(5c-3)=3(3c-5)
We move all terms to the left:
5(5c-3)-(3(3c-5))=0
We multiply parentheses
25c-(3(3c-5))-15=0
We calculate terms in parentheses: -(3(3c-5)), so:We get rid of parentheses
3(3c-5)
We multiply parentheses
9c-15
Back to the equation:
-(9c-15)
25c-9c+15-15=0
We add all the numbers together, and all the variables
16c=0
c=0/16
c=0
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